In this exercise, we shall construct an example of a sequence of random variables that satisfies the weak law of large numbers, but not the strong law. The distribution of Xi will have to depend on i, because otherwise both laws would be satisfied.
Suppose we have an infinite sequence of mutually independent events A1,A2,…. Let ai=P(Ai), and let r be a positive integer.
(a) Find an expression of the probability that none of the Ai with i>r occur.
(b) Use the fact that x−1≤e−x to show that
P(No Ai with i>r occurs)≤e−∑i=r∞ai
(c) (The first Borel-Cantelli lemma) Prove that if ∑i=1∞ai diverges, then
P(infinitely many Ai occur)=1.
Now, let Xi be a sequence of mutually independent random variables such that for each positive integer i≥2,
P(Xi=i)=2ilogi1,P(Xi=−i)=2ilogi1,P(Xi=0)=1−ilogi1.
When i=1 we let Xi=0 with probability 1. As usual we let Sn=X1+⋯+Xn. Note that the mean of each Xi is 0.
(d) Find the variance of Sn.
(e) Show that the sequence ⟨Xi⟩ satisfies the Weak Law of Large Numbers, i.e. prove that for any ϵ>0P(nSn≥ϵ)→0,
as n tends to infinity.
(f) Let Ai be the event ∣Xi∣≥21i. Find P(Ai). Show that ∑i=1∞P(Ai) diverges (use the Integral Test).
(g) Prove that Ai occurs for infinitely many i.
(h) Prove that
P(nSn→0)=0,
and hence that the Strong Law of Large Numbers fails for the sequence {Xi}.