Mathematics

Mathematics

Problem

ddx[eaxcos⁡(bx+c)]=\frac{d}{dx}[e^{ax} \cos(bx + c)] = (a) eax[acos⁡(bx+c)−bsin⁡(bx+c)]e^{ax}[a \cos(bx + c) - b \sin(bx + c)] (b) eax[asin⁡(bx+c)−bcos⁡(bx+c)]e^{ax}[a \sin(bx + c) - b \cos(bx + c)] (c) eax[cos⁡(bx+c)−sin⁡(bx+c)]e^{ax}[\cos(bx + c) - \sin(bx + c)] (d) None of these

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