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Problem
Problem
- Suppose an object has thickness
d
u
du
d
u
so that it extends from object distance
u
u
u
to
u
+
d
u
u + du
u
+
d
u
. Prove that the thickness
d
v
dv
d
v
of its image is given by
(
−
v
2
u
2
)
d
u
\left(-\frac{v^2}{u^2}\right) du
(
−
u
2
v
2
)
d
u
, so the longitudinal magnification
d
v
d
u
=
−
m
2
\frac{dv}{du} = -m^2
d
u
d
v
=
−
m
2
, where
m
m
m
is the lateral magnification.
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