Physics

Physics

Problem

A parallel-plate capacitor of capacitance C0C_0 is charged to a potential V0V_0 and then disconnected from the battery. A dielectric slab of constant κ\kappa is completely inserted between the plates. The new potential difference between the plates is a) V0V_0 b) κV0\kappa V_0 c) V0κ\dfrac{V_0}{\kappa} d) V0κ2\dfrac{V_0}{\kappa^{2}}

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