Linear Algebra and Its Applications · Problem 3.3.31

Orthogonality — Gilbert Strang

Mathematics · recursive-least-squares

Problem

If you know the average x^9\hat{x}_9 of 9 numbers b1,…,b9b_1, \ldots, b_9, how can you quickly find the average x^10\hat{x}_{10} with one more number b10b_{10}? The idea of recursive least squares is to avoid adding 10 numbers. What coefficient of x^9\hat{x}_9 correctly gives x^10\hat{x}_{10}? x^10=110b^10+____ x^9=110(b1+⋯+b10).\hat{x}_{10} = \frac{1}{10}\hat{b}_{10} + \_\_\_\_\, \hat{x}_9 = \frac{1}{10}(b_1 + \cdots + b_{10}).

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