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Mathematics
Mathematics
Problem
If
tan
β
=
n
sin
α
cos
α
1
−
n
sin
2
α
\tan \beta = \frac{n \sin \alpha \cos \alpha}{1 - n \sin^2 \alpha}
tan
β
=
1
−
n
s
i
n
2
α
n
s
i
n
α
c
o
s
α
, show that
tan
(
α
−
β
)
=
(
1
−
n
)
tan
α
\tan(\alpha - \beta) = (1 - n) \tan \alpha
tan
(
α
−
β
)
=
(
1
−
n
)
tan
α
.
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