For a function f, it is known that x→a−limf(x)=2 and x→a+limf(x)=5. Which statement is necessarily true?
a) f is continuous at x=a
b) x→alimf(x) does not exist because the one–sided limits are unequal
c) x→alimf(x) exists and equals 2
d) x→alimf(x) exists and equals 5