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Mathematics
Mathematics
Problem
A solution of the equation
tan
−
1
(
1
+
x
)
+
tan
−
1
(
1
−
x
)
=
π
2
\tan^{-1}(1+x) + \tan^{-1}(1-x) = \frac{\pi}{2}
tan
−
1
(
1
+
x
)
+
tan
−
1
(
1
−
x
)
=
2
π
is (a)
x
=
1
x = 1
x
=
1
(b)
x
=
−
1
x = -1
x
=
−
1
(c)
x
=
0
x = 0
x
=
0
(d)
x
=
π
x = \pi
x
=
π
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