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Mathematics
Problem
Two line whose equation are
x
−
3
2
=
y
−
2
3
=
z
−
1
λ
\frac{x-3}{2} = \frac{y-2}{3} = \frac{z-1}{\lambda}
2
x
−
3
=
3
y
−
2
=
λ
z
−
1
and
x
−
2
3
=
y
−
3
2
=
z
−
2
3
\frac{x-2}{3} = \frac{y-3}{2} = \frac{z-2}{3}
3
x
−
2
=
2
y
−
3
=
3
z
−
2
lie in the same plane, then. Angle between the plane containing both the lines and the plane
4
x
+
y
+
2
z
=
0
4x + y + 2z = 0
4
x
+
y
+
2
z
=
0
is equal to a.
π
3
\frac{\pi}{3}
3
π
b.
π
2
\frac{\pi}{2}
2
π
c.
π
6
\frac{\pi}{6}
6
π
d.
cos
−
1
2
186
\cos^{-1} \frac{2}{\sqrt{186}}
cos
−
1
186
2
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