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Mathematics
Problem
For the curve
λ
x
y
+
y
2
=
12
\lambda xy + y^{2} = 12
λ
x
y
+
y
2
=
12
, find the value of
λ
\lambda
λ
so that the tangent at the point
(
2
,
3
)
(2,3)
(
2
,
3
)
is parallel to the line
14
y
+
3
x
=
0
14y + 3x = 0
14
y
+
3
x
=
0
. a)
−
1
2
-\dfrac{1}{2}
−
2
1
b)
1
2
\dfrac{1}{2}
2
1
c) 2 d)
3
14
\dfrac{3}{14}
14
3
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