Mathematics

Problem

If the distance between the plane

Ax - 2y + z = d

and the plane containing the lines

\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}

and

\frac{x-2}{3} = \frac{y-3}{4} = \frac{z-4}{5}

\sqrt{6}

, then

|d|

is equal to....