Physics

Physics

Problem

A calorimeter of water equivalent 20 g contains 180 g of water at 25∘C25^\circ\text{C} . ' mm ' grams of steam at 100∘C100^\circ\text{C} is mixed in it till the temperature of the mixture is 31∘C31^\circ\text{C} . The value of ' mm ' is close to (Latent heat of water = 540 cal g−1540 \text{ cal g}^{-1} , specific heat of water = 1 cal g−1 ∘C−11 \text{ cal g}^{-1} \text{ }^\circ\text{C}^{-1} ) a. 2 b. 4 c. 3.2 d. 2.6

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