Physics

Physics

Problem

A proton is released from rest at point AA where the electric potential is 500 V500\,\text{V} and moves to point BB where the potential is 200 V200\,\text{V}. Neglecting any non-electrostatic forces, determine the speed of the proton when it reaches BB. (Take e=1.6×10−19 Ce=1.6\times10^{-19}\,\text{C} and mp=1.67×10−27 kgm_p=1.67\times10^{-27}\,\text{kg}.) a) 7.6×105 m s−17.6\times10^{5}\,\text{m s}^{-1} b) 7.6×104 m s−17.6\times10^{4}\,\text{m s}^{-1} c) 2.4×105 m s−12.4\times10^{5}\,\text{m s}^{-1} d) 1.0×107 m s−11.0\times10^{7}\,\text{m s}^{-1}

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