Quantum Mechanics (1) · Problem 4

A few things first

Physics — Quantum Mechanics · galilean-transformations-quantum-mechanics

Problem

Let us consider the action of Galilean transformations on a quantum mechanical wave function. We restrict ourselves here to the ``proper'' Galilean Transformations: (i)(i) translations; (ii)(ii) velocity boosts; (iii)(iii) rotations. We shall consider a transformation to be acting on the state (not on the observer). Thus, a translation by x0\boldsymbol{x}_0 on a state localized at x1\boldsymbol{x}_1 produces a new state, localized at x1+x0\boldsymbol{x}_1 + \boldsymbol{x}_0. In ``configuration space'', we have a wave function of the form ψ(x,t)\psi(\boldsymbol{x}, t). A translation T(x0)T(\boldsymbol{x}_0) by x0\boldsymbol{x}_0 of this state yields a new state: ψ′(x)=T(x0)ψ(x,t)=ψ(x−x0,t).(1.122)\psi'(\boldsymbol{x}) = T(\boldsymbol{x}_0)\psi(\boldsymbol{x}, t) = \psi(\boldsymbol{x} - \boldsymbol{x}_0, t). \tag{1.122} Consider a free particle of mass mm. The momentum space wave function is ψ^(p,t)=f^(p)exp⁡(−itp22m),(1.123)\hat{\psi}(\boldsymbol{p}, t) = \hat{f}(\boldsymbol{p}) \exp\left(-\frac{itp^2}{2m}\right), \tag{1.123} where p=∣p∣p = |\boldsymbol{p}|. The configuration space wave function is related by the (inverse) Fourier transform: ψ(x,t)=1(2π)3/2∫(∞)d3(p) eix⋅pψ^(p,t).(1.124)\psi(\boldsymbol{x}, t) = \frac{1}{(2\pi)^{3/2}} \int_{(\infty)} d^3(\boldsymbol{p})\, e^{i\boldsymbol{x}\cdot\boldsymbol{p}} \hat{\psi}(\boldsymbol{p}, t). \tag{1.124} Obtain simple transformation laws, on both the momentum and configuration space wave functions, for each of the following proper Galilean transformations: (a) Translation by x0\boldsymbol{x}_0: T(x0)T(\boldsymbol{x}_0) (note that we have already seen the result in configuration space). (b) Translation by time t0t_0: M(t0)M(t_0). (c) Velocity boost by v0\boldsymbol{v}_0: V(v0)V(\boldsymbol{v}_0). (Hint: first find ψ^′(p,0)=f^′(p)=V(v0)f^(p),(1.125)\hat{\psi}'(\boldsymbol{p}, 0) = \hat{f}'(\boldsymbol{p}) = V(\boldsymbol{v}_0)\hat{f}(\boldsymbol{p}), \tag{1.125} then ψ^′(p,t)=f^′(p)e−itp2/2m,(1.126)\hat{\psi}'(\boldsymbol{p}, t) = \hat{f}'(\boldsymbol{p})e^{-itp^2/2m}, \tag{1.126} etc.) (d) Rotation about the origin given by 3×33 \times 3 matrix RR: U(R)U(R). Make sure your answers make sense to you in terms of classical correspondence.

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