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Problem If ∫ e x − 1 ( x 2 − 5 x + 4 ) 2 ⋅ 2 x d x = A F ( x − 1 ) + B F ( x − 4 ) + c \int \frac{e^{x-1}}{(x^2-5x+4)^2} \cdot 2x\,dx = AF(x-1) + BF(x-4) + c ∫ ( x 2 − 5 x + 4 ) 2 e x − 1 ⋅ 2 x d x = A F ( x − 1 ) + B F ( x − 4 ) + c F ( x ) = ∫ e x x d x F(x) = \int \frac{e^x}{x} dx F ( x ) = ∫ x e x d x A A A B B B ( − 2 3 , 8 3 ) \left( -\frac{2}{3}, \frac{8}{3} \right) ( − 3 2 , 3 8 ) ( − 2 3 , 8 e 3 3 ) \left( -\frac{2}{3}, \frac{8e^3}{3} \right) ( − 3 2 , 3 8 e 3 ) ( 8 3 , 2 3 ) \left( \frac{8}{3}, \frac{2}{3} \right) ( 3 8 , 3 2 ) ( − 2 3 , − 8 e 3 3 ) \left( -\frac{2}{3}, -\frac{8e^3}{3} \right) ( − 3 2 , − 3 8 e 3 ) ( − 2 3 , 8 3 ) \left( -\frac{2}{3}, \frac{8}{3} \right) ( − 3 2 , 3 8 ) ( − 2 3 , 8 e 3 3 ) \left( -\frac{2}{3}, \frac{8e^3}{3} \right) ( − 3 2 , 3 8 e 3 ) ( 8 3 , 2 3 ) \left( \frac{8}{3}, \frac{2}{3} \right) ( 3 8 , 3 2 ) ( − 2 3 , − 8 e 3 3 ) \left( -\frac{2}{3}, -\frac{8e^3}{3} \right) ( − 3 2 , − 3 8 e 3 ) Browse the problem library