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Mathematics
Mathematics
Problem
Consider
f
(
x
)
=
{
[
x
]
+
∣
x
−
1
∣
+
1
}
f(x) = \{[x] + |x-1| + 1\}
f
(
x
)
=
{[
x
]
+
∣
x
−
1∣
+
1
}
. Find the number of solution(s) of the equation
3
f
(
f
(
x
)
)
−
1
=
0
in
[
−
2
,
4
]
3f(f(x)) - 1 = 0 \text{ in } [-2, 4]
3
f
(
f
(
x
))
−
1
=
0
in
[
−
2
,
4
]
[Note:
[
y
]
[y]
[
y
]
and
{
y
}
\{y\}
{
y
}
denotes greatest integer function less than or equal to
y
y
y
and fraction part function of
y
y
y
, respectively.]
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