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Problem ∫ x 3 x 2 + 2 d x = \int \frac{x^3}{\sqrt{x^2 + 2}}\,dx = ∫ x 2 + 2 x 3 d x = 1 3 ( x 2 + 2 ) 3 / 2 + 2 ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} + 2(x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 + 2 ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 − 2 ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} - 2(x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 − 2 ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 + ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} + (x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 + ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 − ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} - (x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 − ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 + 2 ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} + 2(x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 + 2 ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 − 2 ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} - 2(x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 − 2 ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 + ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} + (x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 + ( x 2 + 2 ) 1/2 + c 1 3 ( x 2 + 2 ) 3 / 2 − ( x 2 + 2 ) 1 / 2 + c \frac{1}{3}(x^2 + 2)^{3/2} - (x^2 + 2)^{1/2} + c 3 1 ( x 2 + 2 ) 3/2 − ( x 2 + 2 ) 1/2 + c Browse the problem library