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Mathematics
Mathematics
Problem
Let
y
=
y
(
x
)
y = y(x)
y
=
y
(
x
)
be the solution of the differential equation
sec
x
d
y
+
{
2
(
1
−
x
)
tan
x
+
x
(
2
−
x
)
}
d
x
=
0
\sec x dy + \{2(1-x)\tan x + x(2-x)\}dx = 0
sec
x
d
y
+
{
2
(
1
−
x
)
tan
x
+
x
(
2
−
x
)}
d
x
=
0
such that
y
(
0
)
=
2
y(0) = 2
y
(
0
)
=
2
. Then
y
(
2
)
y(2)
y
(
2
)
is equal to : A 2 B
2
{
1
−
sin
(
2
)
}
2\{1 - \sin(2)\}
2
{
1
−
sin
(
2
)}
C
2
{
sin
(
2
)
+
1
}
2\{\sin(2) + 1\}
2
{
sin
(
2
)
+
1
}
D 1
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