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Mathematics
Mathematics
Problem
In
△
A
B
C
\triangle ABC
△
A
B
C
,
A
B
=
(
5
x
−
1
)
cm
AB = (5x-1)\,\text{cm}
A
B
=
(
5
x
−
1
)
cm
and
A
C
=
12
cm
AC = 12\,\text{cm}
A
C
=
12
cm
. In
△
D
E
F
\triangle DEF
△
D
E
F
,
D
E
=
(
2
x
+
8
)
cm
DE = (2x+8)\,\text{cm}
D
E
=
(
2
x
+
8
)
cm
and
D
F
=
12
cm
DF = 12\,\text{cm}
D
F
=
12
cm
. If
∠
B
A
C
=
∠
E
D
F
\angle BAC = \angle EDF
∠
B
A
C
=
∠
E
D
F
and the two triangles are congruent by the SAS criterion, then the value of
x
x
x
is a)
13
5
\dfrac{13}{5}
5
13
b)
2
2
2
c)
3
3
3
d)
7
3
\dfrac{7}{3}
3
7
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