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Mathematics
Mathematics
Problem
If the integral
∫
5
tan
x
tan
x
−
2
d
x
=
x
+
a
log
∣
sin
x
−
2
cos
x
∣
+
k
\int \frac{5 \tan x}{\tan x - 2}\,dx = x + a \log|\sin x - 2 \cos x| + k
∫
t
a
n
x
−
2
5
t
a
n
x
d
x
=
x
+
a
lo
g
∣
sin
x
−
2
cos
x
∣
+
k
, then
a
a
a
is equal to a. -1 b. -2 c. 1 d. 2
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