Mathematics

Mathematics

Problem

Let a circle C1C_1 be obtained on rolling the circle x2+y2−4x−6y+11=0x^2 + y^2 - 4x - 6y + 11 = 0 upwards 4 units on the tangent TT to it at the point (3,2)(3, 2). Let C2C_2 be the image of C1C_1 in TT. Let AA and BB be the centers of circles C1C_1 and C2C_2 respectively, and MM and NN be respectively the feet of perpendiculars drawn from AA and BB on the xx-axis. Then the area of the trapezium AMNBAMNB is: [Main Jan. 31, 2023 (I)] (a) 2(2+2)2(2 + \sqrt{2}) (b) 4(1+2)4(1 + \sqrt{2}) (c) 3+223 + 2\sqrt{2} (d) 2(1+2)2(1 + \sqrt{2})

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