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Mathematics
Problem
The coordinates of a point on the line
x
−
1
2
=
y
+
1
−
3
=
z
\frac{x-1}{2} = \frac{y+1}{-3} = z
2
x
−
1
=
−
3
y
+
1
=
z
at a distance
4
14
4\sqrt{14}
4
14
from the point
(
1
,
−
1
,
0
)
(1, -1, 0)
(
1
,
−
1
,
0
)
are a.
(
9
,
−
13
,
4
)
(9, -13, 4)
(
9
,
−
13
,
4
)
b.
(
8
14
+
1
,
−
12
14
−
1
,
4
14
)
(8\sqrt{14} + 1, -12\sqrt{14} - 1, 4\sqrt{14})
(
8
14
+
1
,
−
12
14
−
1
,
4
14
)
c.
(
−
7
,
11
,
−
4
)
(-7, 11, -4)
(
−
7
,
11
,
−
4
)
d.
(
−
8
14
+
1
,
12
14
−
1
,
−
4
14
)
(-8\sqrt{14} + 1, 12\sqrt{14} - 1, -4\sqrt{14})
(
−
8
14
+
1
,
12
14
−
1
,
−
4
14
)
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