Determine whether the series n=2∑∞n(lnn)31 converges or diverges.
a) It diverges because substituting u=lnx incorrectly gives ∫u1du, which is unbounded.
b) It diverges because the logarithm grows too slowly, so the terms behave like the harmonic series 1/n.
c) The series converges because ∫2∞x(lnx)31dx is finite; by the Integral Test, the series therefore converges.
d) It diverges; the Ratio Test gives a limit of 1, which demonstrates divergence.