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If
I
=
2
π
∫
−
π
/
4
π
/
4
d
x
(
1
+
e
sin
x
)
(
2
−
cos
2
x
)
I = \frac{2}{\pi} \int_{-\pi/4}^{\pi/4} \frac{dx}{(1 + e^{\sin x})(2 - \cos 2x)}
I
=
π
2
∫
−
π
/4
π
/4
(
1
+
e
s
i
n
x
)
(
2
−
cos
2
x
)
d
x
…
Mathematics
Problem
If
I
=
2
π
∫
−
π
/
4
π
/
4
d
x
(
1
+
e
sin
x
)
(
2
−
cos
2
x
)
I = \frac{2}{\pi} \int_{-\pi/4}^{\pi/4} \frac{dx}{(1 + e^{\sin x})(2 - \cos 2x)}
I
=
π
2
∫
−
π
/4
π
/4
(
1
+
e
s
i
n
x
)
(
2
−
cos
2
x
)
d
x
then
27
I
2
27 I^2
27
I
2
equals ___.
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