Blundell Thermal Physics · Problem 30.4

Quantum gases and condensates

Physics — Statistical Mechanics · bose-gas-heat-capacity

Problem

Show that the heat capacity of a system of non-interacting bosons is given by CV=154ζ(52)ζ(32)NkB(TTc)3/2,T<Tc,CV=32NkB(52Li5/2(z)Li3/2(z)−32Li3/2(z)Li1/2(z)),T>Tc.(30.65)\begin{aligned} C_V &= \frac{15}{4}\frac{\zeta(\frac{5}{2})}{\zeta(\frac{3}{2})}Nk_{\rm B}\left(\frac{T}{T_{\rm c}}\right)^{3/2}, \quad T < T_{\rm c}, \nonumber\\ C_V &= \frac{3}{2}Nk_{\rm B}\left(\frac{5}{2}\frac{{\rm Li}_{5/2}(z)}{{\rm Li}_{3/2}(z)} - \frac{3}{2}\frac{{\rm Li}_{3/2}(z)}{{\rm Li}_{1/2}(z)}\right), \quad T > T_{\rm c}. \tag{30.65} \end{aligned}

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