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Physics
Physics
Problem
A proton moves in a circle of radius
2.0
cm
2.0\,\text{cm}
2.0
cm
in a uniform magnetic field of
0.20
T
0.20\,\text{T}
0.20
T
, the velocity being perpendicular to the field. Calculate its kinetic energy. (Take
e
=
1.6
×
10
−
19
C
e=1.6\times10^{-19}\,\text{C}
e
=
1.6
×
1
0
−
19
C
,
m
p
=
1.67
×
10
−
27
kg
m_p=1.67\times10^{-27}\,\text{kg}
m
p
=
1.67
×
1
0
−
27
kg
.) a)
7.7
×
10
3
eV
7.7\times10^{3}\,\text{eV}
7.7
×
1
0
3
eV
b)
7.7
×
10
2
eV
7.7\times10^{2}\,\text{eV}
7.7
×
1
0
2
eV
c)
1.9
×
10
2
eV
1.9\times10^{2}\,\text{eV}
1.9
×
1
0
2
eV
d)
1.5
×
10
3
eV
1.5\times10^{3}\,\text{eV}
1.5
×
1
0
3
eV
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