Mathematics

Mathematics

Problem

Let f(x)=(1+cos⁡x)22x−πf(x) = (1 + \cos x)^{\frac{2}{2x - \pi}} , x≠π2x \neq \frac{\pi}{2} . If f(x)f(x) is continuous at x=π2x = \frac{\pi}{2} , then the value of f(π2)f\left(\frac{\pi}{2}\right) is - (A) 1 (B) -1 (C) 1e\frac{1}{e} (D) ee

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