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Problem State whether A ⊆ B A \subseteq B A ⊆ B A = ∅ A = \emptyset A = ∅ B = { 2 , 5 , 7 , 9 } B = \{2, 5, 7, 9\} B = { 2 , 5 , 7 , 9 } A = { 2 , 5 , 8 , 9 } A = \{2, 5, 8, 9\} A = { 2 , 5 , 8 , 9 } B = { 8 , 9 } B = \{8, 9\} B = { 8 , 9 } A = { x ∈ R ∣ 2 ≤ x ≤ 3 } A = \{x \in \mathbb{R} \mid 2 \le x \le 3\} A = { x ∈ R ∣ 2 ≤ x ≤ 3 } B = { x ∈ R } B = \{x \in \mathbb{R}\} B = { x ∈ R } A = { x ∈ Q ∣ 3 ≤ x ≤ 9 } A = \{x \in \mathbb{Q} \mid 3 \le x \le 9\} A = { x ∈ Q ∣ 3 ≤ x ≤ 9 } B = { x ∈ R ∣ 0 ≤ x ≤ 10 } B = \{x \in \mathbb{R} \mid 0 \le x \le 10\} B = { x ∈ R ∣ 0 ≤ x ≤ 10 } A = { x ∈ Z ∣ − 10 ≤ x ≤ 10 } A = \{x \in \mathbb{Z} \mid -10 \le x \le 10\} A = { x ∈ Z ∣ − 10 ≤ x ≤ 10 } B = { z ∈ Z ∣ 0 ≤ z ≤ 5 } B = \{z \in \mathbb{Z} \mid 0 \le z \le 5\} B = { z ∈ Z ∣ 0 ≤ z ≤ 5 } A = { x ∈ Q ∣ 0 ≤ x ≤ 1 } A = \{x \in \mathbb{Q} \mid 0 \le x \le 1\} A = { x ∈ Q ∣ 0 ≤ x ≤ 1 } B = { y ∈ Q ∣ 0 < y ≤ 2 } B = \{y \in \mathbb{Q} \mid 0 < y \le 2\} B = { y ∈ Q ∣ 0 < y ≤ 2 } Browse the problem library