Problem

A pot with a steel bottom 1.2 cm thick rests on a hot stove. The area of the bottom of the pot is

0.150 \text{ m}^2

. The water inside the pot is at

100^{\circ}\text{C}

and 0.440 kg are evaporated every 5.0 minute. Find the temperature of the lower surface of the pot, which is in contact with the stove. Take

L_v = 2.256 \times 10^6 \text{ J/kg}

and

k_{\text{steel}} = 50.2 \text{ W/m}\cdot\text{K}