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Mathematics
Mathematics
Problem
Consider the function
g
(
x
)
=
{
∣
x
∣
x
,
x
≠
0
,
1
,
x
=
0.
g(x)=\begin{cases} \dfrac{|x|}{x}, & x\neq 0,\\[2pt] 1, & x=0. \end{cases}
g
(
x
)
=
⎩
⎨
⎧
x
∣
x
∣
,
1
,
x
=
0
,
x
=
0.
Is
g
g
g
continuous at
x
=
0
x=0
x
=
0
? Give a brief reason for your answer.
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