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Mathematics
Mathematics
Problem
Determine
g
′
′
′
(
θ
)
g'''(\theta)
g
′′′
(
θ
)
for
g
(
θ
)
=
cos
(
3
θ
)
g(\theta)=\cos(3\theta)
g
(
θ
)
=
cos
(
3
θ
)
. a)
−
9
cos
3
θ
-9\cos 3\theta
−
9
cos
3
θ
b)
27
sin
3
θ
27\sin 3\theta
27
sin
3
θ
c)
27
cos
3
θ
27\cos 3\theta
27
cos
3
θ
d)
−
27
sin
3
θ
-27\sin 3\theta
−
27
sin
3
θ
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