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Mathematics
Problem
The solution of the differential equation
y
d
x
−
(
x
+
2
y
2
)
d
y
=
0
y\,dx-(x+2y^2)\,dy=0
y
d
x
−
(
x
+
2
y
2
)
d
y
=
0
is
x
=
f
(
y
)
x=f(y)
x
=
f
(
y
)
. If
f
(
−
1
)
=
1
f(-1)=1
f
(
−
1
)
=
1
, then
f
(
1
)
f(1)
f
(
1
)
is equal to : [JEE-MAIN ONLINE-2015] (1) 1 (2) 4 (3) 3 (4) 2
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