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Problem
Problem
A triangle
A
B
C
ABC
A
B
C
is inscribed in a circle of radius 1 and centre at
O
O
O
. The lines
A
O
,
B
O
,
C
O
AO, BO, CO
A
O
,
B
O
,
C
O
meet the opposite sides at
D
,
E
,
F
D, E, F
D
,
E
,
F
. Then
1
A
D
+
1
B
E
+
1
C
F
\frac{1}{AD} + \frac{1}{BE} + \frac{1}{CF}
A
D
1
+
B
E
1
+
C
F
1
is equal to .....
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