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Mathematics
Problem
If
x
x
x
is real, then maximum value of
3
x
2
+
9
x
+
17
3
x
2
+
9
x
+
7
\frac{3x^2+9x+17}{3x^2+9x+7}
3
x
2
+
9
x
+
7
3
x
2
+
9
x
+
17
is: (a) 41 (b) 1 (c)
17
7
\frac{17}{7}
7
17
(d)
1
4
\frac{1}{4}
4
1
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