Problem

Problem

If xn+1=1+xn2x_{n+1} = \sqrt{\frac{1+x_n}{2}} and ∣x0∣<1,n≥0|x_0| < 1, n \ge 0 , then lim⁡n→∞(1−x02x1x2x3…xn+1)\lim_{n \to \infty} \left( \frac{\sqrt{1-x_0^2}}{x_1 x_2 x_3 \dots x_{n+1}} \right) is equal to a. −1-1 b. 1 c. cos⁡−1(x0+1)\cos^{-1}(x_0 + 1) d. cos⁡−1(x0)\cos^{-1}(x_0)

Browse the problem library