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Mathematics
Mathematics
Problem
If the two circles
2
x
2
+
2
y
2
−
3
x
+
6
y
+
k
=
0
2x^2 + 2y^2 - 3x + 6y + k = 0
2
x
2
+
2
y
2
−
3
x
+
6
y
+
k
=
0
and
x
2
+
y
2
−
4
x
+
10
y
+
16
=
0
x^2 + y^2 - 4x + 10y + 16 = 0
x
2
+
y
2
−
4
x
+
10
y
+
16
=
0
cut orthogonally, then the value of
k
k
k
is- (1) 41 (2) 14 (3) 4 (4) 0
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