Mathematics

Mathematics

Problem

5. For g(x)=tan⁡(3x2)(1+2x)3g(x)=\dfrac{\tan(3x^{2})}{(1+2x)^{3}}, evaluate g′(1)g'(1). a) 6sec⁡23−2tan⁡39\displaystyle \frac{6\sec^{2}3-2\tan3}{9} b) 6sec⁡2327\displaystyle \frac{6\sec^{2}3}{27} c) 6sec⁡23−2tan⁡327\displaystyle \frac{6\sec^{2}3-2\tan3}{27} d) sec⁡23−2tan⁡327\displaystyle \frac{\sec^{2}3-2\tan3}{27}

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