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Mathematics
Mathematics
Problem
5. For
g
(
x
)
=
tan
(
3
x
2
)
(
1
+
2
x
)
3
g(x)=\dfrac{\tan(3x^{2})}{(1+2x)^{3}}
g
(
x
)
=
(
1
+
2
x
)
3
tan
(
3
x
2
)
, evaluate
g
′
(
1
)
g'(1)
g
′
(
1
)
. a)
6
sec
2
3
−
2
tan
3
9
\displaystyle \frac{6\sec^{2}3-2\tan3}{9}
9
6
sec
2
3
−
2
tan
3
b)
6
sec
2
3
27
\displaystyle \frac{6\sec^{2}3}{27}
27
6
sec
2
3
c)
6
sec
2
3
−
2
tan
3
27
\displaystyle \frac{6\sec^{2}3-2\tan3}{27}
27
6
sec
2
3
−
2
tan
3
d)
sec
2
3
−
2
tan
3
27
\displaystyle \frac{\sec^{2}3-2\tan3}{27}
27
sec
2
3
−
2
tan
3
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