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Mathematics
Mathematics
Problem
The hyperbola
x
2
25
−
y
2
144
=
1
\dfrac{x^{2}}{25}-\dfrac{y^{2}}{144}=1
25
x
2
−
144
y
2
=
1
has semi-transverse axis
a
=
5
a=5
a
=
5
and semi-conjugate axis
b
=
12
b=12
b
=
12
. a. (i) Calculate the distance
c
c
c
of each focus from the centre. b. (ii) Hence find the eccentricity
e
e
e
of the hyperbola.
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