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Problems
f
(
x
)
=
∣
x
3
x
2
3
x
2
1
−
6
4
p
p
2
p
3
∣
f(x) = \begin{vmatrix} x^3 & x^2 & 3x^2 \\ 1 & -6 & 4 \\ p & p^2 & p^3 \end{vmatrix}
f
(
x
)
=
x
3
1
p
x
2
−
6
p
2
3
x
2
4
p
3
, he…
Mathematics
Problem
f
(
x
)
=
∣
x
3
x
2
3
x
2
1
−
6
4
p
p
2
p
3
∣
f(x) = \begin{vmatrix} x^3 & x^2 & 3x^2 \\ 1 & -6 & 4 \\ p & p^2 & p^3 \end{vmatrix}
f
(
x
)
=
x
3
1
p
x
2
−
6
p
2
3
x
2
4
p
3
, here
p
p
p
is a constant, then
d
3
f
(
x
)
d
x
3
\frac{d^3 f(x)}{dx^3}
d
x
3
d
3
f
(
x
)
is (a) Proportional to
x
2
x^2
x
2
(b) Proportional to
x
x
x
(c) Proportional to
x
3
x^3
x
3
(d) A constant
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