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Chemistry
Chemistry
Problem
What volume of a solution of hydrochloric acid with a concentration of
0.250
mol dm
−
3
0.250 \text{ mol dm}^{-3}
0.250
mol dm
−
3
would be required to react with 0.25 g of calcium carbonate?
CaCO
3
(
s
)
+
2
HCl
(
aq
)
→
CaCl
2
(
aq
)
+
H
2
O
(
l
)
+
CO
2
(
g
)
\text{CaCO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{CaCl}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g})
CaCO
3
(
s
)
+
2
HCl
(
aq
)
→
CaCl
2
(
aq
)
+
H
2
O
(
l
)
+
CO
2
(
g
)
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