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Mathematics
Mathematics
Problem
Prove that: 1.
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
\sin ^{2} \frac{\pi}{6}+\cos ^{2} \frac{\pi}{3}-\tan ^{2} \frac{\pi}{4}=-\frac{1}{2}
sin
2
6
π
+
cos
2
3
π
−
tan
2
4
π
=
−
2
1
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