Physics

Physics

Problem

A particle is projected from the ground with velocity u⃗=(30i^+40j^) m/s\vec{u} = (30\hat{i} + 40\hat{j})\,\text{m/s}. It lands on a horizontal elevated surface. At the moment of impact, the velocity vector of the particle makes an angle of 37∘37^{\circ} with the horizontal. Find the height of the elevated surface. (Take g=10 m/s2g = 10\,\text{m/s}^{2}, tan⁡37∘=0.75\tan 37^{\circ} = 0.75)

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