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Mathematics
Mathematics
Problem
If
f
(
x
)
=
x
+
1
x
−
1
f(x) = \frac{x+1}{x-1}
f
(
x
)
=
x
−
1
x
+
1
and
g
(
x
)
=
1
x
−
2
g(x) = \frac{1}{x-2}
g
(
x
)
=
x
−
2
1
, then
(
f
∘
g
)
(
x
)
(f \circ g)(x)
(
f
∘
g
)
(
x
)
is discontinuous at a.
x
=
3
x=3
x
=
3
only b.
x
=
2
x=2
x
=
2
only c.
x
=
2
x=2
x
=
2
and
3
3
3
only d.
x
=
1
x=1
x
=
1
only
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