Complex Analysis: Theory and Applications · Problem 5.1.14

Elementary Functions — Howell & Matthews

Mathematics — Complex Analysis · complex-exponential-powers

Problem

Let nn be a positive integer. Show that ((a)) (exp⁡z)n=exp⁡(nz)(\exp z)^n = \exp(nz). ((b)) 1(exp⁡z)n=exp⁡(−nz)\dfrac{1}{(\exp z)^n} = \exp(-nz).

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