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Problem
The atomic masses of Li, He and proton are 7.01823 amu, 4.00387 amu and 1.00715 amu respectively. Calculate the energy evolved in the reaction,
3
7
Li
+
1
1
p
→
2
2
4
He
+
Δ
E
^{7}_{3}\text{Li} + {}^{1}_{1}\text{p} \rightarrow 2\,{}^{4}_{2}\text{He} + \Delta E
3
7
Li
+
1
1
p
→
2
2
4
He
+
Δ
E
Given 1 amu = 931 MeV.
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