Physics

Physics

Problem

A block of mass 2 kg moving on a horizontal surface with speed of 4 ms−14 \text{ ms}^{-1} enters a rough surface ranging from x=0.5 mx = 0.5 \text{ m} to x=1.5 mx = 1.5 \text{ m}. The retarding force in this range of rough surface is related to distance by F=−kxF = -kx where k=12 Nm−1k = 12 \text{ Nm}^{-1}. The speed of the block as it just crosses the rough surface will be: (a) Zero (b) 1.5 ms−11.5 \text{ ms}^{-1} (c) 2.0 ms−12.0 \text{ ms}^{-1} (d) 2.5 ms−12.5 \text{ ms}^{-1} [June 28, 2022 (II)]

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