The proof of formula B.28 is by induction.
(a) Check formula B.28 for n=0 and for n=1.
(b) Show that
∫0π(sinθ)ndθ=(nn−1)∫0π(sinθ)n−2dθ.
(Hint: First write (sinθ)n as (sinθ)n−2(1−cos2θ). Integrate the second term by parts, differentiating one factor of cosθ and integrating everything else.)
(c) Use the results of parts (a) and (b) to prove formula B.28 by induction.