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Problem
The manufacture of sulfur trioxide can be represented by the equation below:
2
SO
2
(
g
)
+
O
2
(
g
)
⇌
2
SO
3
(
g
)
Δ
H
=
−
198
kJ mol
−
1
2\text{SO}_2(\text{g}) + \text{O}_2(\text{g}) \rightleftharpoons 2\text{SO}_3(\text{g}) \quad \Delta H = -198 \text{ kJ mol}^{-1}
2
SO
2
(
g
)
+
O
2
(
g
)
⇌
2
SO
3
(
g
)
Δ
H
=
−
198
kJ mol
−
1
What happens when a catalyst is added to an equilibrium mixture from this reaction?
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