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Mathematics
Problem
When investigating the convergence of the series
∑
n
=
1
∞
1
n
3
\displaystyle\sum_{n=1}^{\infty}\frac{1}{n^{3}}
n
=
1
∑
∞
n
3
1
, which improper integral is directly associated with the terms of the series? a)
∫
1
∞
1
x
2
d
x
\displaystyle \int_{1}^{\infty}\frac{1}{x^{2}}\,dx
∫
1
∞
x
2
1
d
x
b)
∫
0
1
1
x
3
d
x
\displaystyle \int_{0}^{1}\frac{1}{x^{3}}\,dx
∫
0
1
x
3
1
d
x
c)
∫
1
∞
1
x
3
d
x
\displaystyle \int_{1}^{\infty}\frac{1}{x^{3}}\,dx
∫
1
∞
x
3
1
d
x
d)
∫
1
∞
1
x
3
/
2
d
x
\displaystyle \int_{1}^{\infty}\frac{1}{x^{3/2}}\,dx
∫
1
∞
x
3/2
1
d
x
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