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Problem
Problem
If
∣
x
2
−
5
∣
x
∣
+
6
∣
=
k
|x^2 - 5|x| + 6| = k
∣
x
2
−
5∣
x
∣
+
6∣
=
k
, has 8 distinct solution then 'k' lies in (a)
(
−
∞
,
0
)
(-\infty, 0)
(
−
∞
,
0
)
(b)
(
0
,
∞
)
(0, \infty)
(
0
,
∞
)
(c)
(
0
,
1
4
)
\left(0, \frac{1}{4}\right)
(
0
,
4
1
)
(d)
(
1
4
,
6
)
\left(\frac{1}{4}, 6\right)
(
4
1
,
6
)
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